[MYSQL] SELECT select FROM Programmers

 

 

 

문제 정보

 

SELECT * FROM ANIMAL_INS ORDER BY ANIMAL_ID;

 

 

SELECT NAME, DATETIME FROM ANIMAL_INS ORDER BY ANIMAL_ID DESC;

 

 

SELECT ANIMAL_ID, NAME FROM ANIMAL_INS WHERE INTAKE_CONDITION = 'Sick';

 

 

SELECT ANIMAL_ID, NAME FROM ANIMAL_INS WHERE NOT INTAKE_CONDITION = 'Aged';

 

 

SELECT ANIMAL_ID, NAME FROM ANIMAL_INS ORDER BY ANIMAL_ID;

 

 

SELECT ANIMAL_ID, NAME, DATETIME FROM ANIMAL_INS ORDER BY NAME, DATETIME DESC;

 

 

SELECT NAME FROM ANIMAL_INS WHERE DATETIME = (SELECT MIN(DATETIME) FROM ANIMAL_INS);